In C++ (default arguments and pre-increment effects), evaluate the function call and compute the exact integer result. #include<iostream.h> long CuriousTabFunction(int x, int y = 5, float z = 5) { return (++x * ++y + (int)++z); } int main() { cout << CuriousTabFunction(20, 10); return 0; }

Introduction / Context:
This checks your fluency with default parameters, pre-increment semantics, and casts from floating point to integer in C++. The order of operations is explicit because increments occur on local parameters before multiplication and addition in a straightforward expression.

Given Data / Assumptions:

• Call: CuriousTabFunction(20, 10) → x=20, y=10, z=5 (default for z).
• Expression: ++x * ++y + (int)++z.

Concept / Approach:
Pre-increment increases the operand and yields the incremented value. Casting a float to int truncates toward zero. Multiplication and addition then combine these updated values deterministically (no sequencing pitfalls here because the operands do not alias the same object).

Step-by-Step Solution:

Verification / Alternative check:
Evaluating on paper or in a small REPL reproduces the same deterministic steps since there is no undefined behavior in this expression.

Why Other Options Are Wrong:

• 242 or 240: Miscalculations of either the product or casted addend.
• 35: Treats increments as if unused or misapplies operator precedence.
• Compilation error: The code is well-formed under classic headers.

Common Pitfalls:
Forgetting that ++z happens before the cast and truncation, or mixing up pre- vs post-increment results.

Final Answer:
237