In C++ (iostream.h), a class method with default parameters modifies members and prints an expression using pre-increment and pre-decrement. Determine the output. #include void Tester(int xx, int yy = 5); // unrelated free function class CuriousTab { int x; int y; public: void Tester(int xx, int yy = 5) { x = xx; y = yy; cout << ++x % --y; } }; int main() { CuriousTab objCuriousTab; objCuriousTab.Tester(5, 5); return 0; }

Introduction / Context: The problem focuses on default parameters and operator semantics in C++. It asks you to evaluate an expression that uses pre-increment and pre-decrement with integer operands and the modulo operator, all inside a class method invoked with explicit arguments.

Given Data / Assumptions:

• Method Tester(int, int = 5) is called as Tester(5, 5).
• Computation: cout << ++x % --y; with integer x and y.
• Free function Tester declared above is unrelated to the member call.

Concept / Approach: Pre-increment ++x yields 6. Pre-decrement --y yields 4. The modulo operation with integers computes 6 % 4, which equals 2. The method prints this result directly.

Step-by-Step Solution:

Verification / Alternative check: Replacing pre- with post- (x++ % y--) would evaluate to 5 % 5 → 0 first, but the code explicitly uses pre-operators, so the printed result is 2.

Why Other Options Are Wrong:

• The program will print the output 0./1.: Do not match 6 % 4.
• The program will print the output garbage value.: All variables are well-defined.
• The program will report compile time error.: There is no ambiguity; member call resolves correctly.

Common Pitfalls: Confusing the free Tester declaration with the class method; mixing up pre- and post- increments which change the numeric result; overlooking that modulo is only valid for integral types (which we have here).

Final Answer: The program will print the output 2.