Consider the following table of inverse variation : | M | 15 | -6 | 2 | C | |---|---|---|---|---| | N | -4 | A | B | 60 | The values of $A$, $B$ and $C$ in the above table respectively are

### Concept & Inverse Variation Two variables $M$ and $N$ are in inverse variation (or inversely proportional) if their product is a constant. $$M \times N = k$$ ### Step-by-Step Solution * **Find the constant $k$**: Using the first fully known column: $k = 15 \times (-4) = -60$ * **Find $A$**: $(-6) \times A = -60 \implies A = \frac{-60}{-6} = 10$ * **Find $B$**: $2 \times B = -60 \implies B = \frac{-60}{2} = -30$ * **Find $C$**: $C \times 60 = -60 \implies C = \frac{-60}{60} = -1$ * The values for $A$, $B$, and $C$ respectively are $10$, $-30$, and $-1$. ### Exam Strategy & Shortcut Find $k$ quickly from the first pair ($15 \times -4 = -60$). Then, look at the options. We know $C$ must be $-1$ because $C \times 60 = -60$. The only options ending in $-1$ are (b) and (c). We calculate $A = 10$, eliminating (b). ### Common Pitfall Misinterpreting "inverse variation" as direct variation (where ratio is constant instead of product), which would lead to incorrect calculations. ### Final Answer Therefore, the correct answer is **10, -30, -1**.