C++ templates: regarding a template function's generic parameter name, which statement is correct?

Difficulty: Easy

Correct Answer: can be T

Explanation:


Introduction / Context:
Template functions in C++ introduce type parameters using identifiers declared in a template parameter list. While 'T' is a traditional, short name used in examples, the language imposes no requirement to use that specific identifier. Understanding this clarifies template readability and naming conventions in real-world codebases.


Given Data / Assumptions:

  • We are discussing function templates, not only class templates.
  • The template parameter identifier is programmer-chosen.
  • Names must follow C++ identifier rules and be unique within the template parameter list.


Concept / Approach:

  • A template parameter list might look like: template or template.
  • The identifier (T, U, ValueType, Key, etc.) can be any valid name.
  • Style guides often encourage descriptive names for clarity in generic code.


Step-by-Step Reasoning:

Recognize that 'T' is conventional but not mandatory.Confirm by examples: template ValueType max(ValueType a, ValueType b).Therefore, the correct statement is that the generic type can be named T, among many other legal names.


Verification / Alternative check:

Inspect standard library templates: identifiers vary widely (T, U, CharT, Traits, Allocator), demonstrating flexibility in naming.


Why Other Options Are Wrong:

  • must be T / cannot be T: Both contradict the language rules that impose no such restriction.
  • cannot be T for user functions: No special privilege exists for standard library vs user code.
  • None of the above: Incorrect because 'can be T' accurately reflects reality.


Common Pitfalls:

  • Overusing single-letter names in complex templates where descriptive names improve clarity.
  • Confusing 'class' and 'typename' in parameter lists; both are valid keywords for type parameters.


Final Answer:

can be T

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