Difficulty: Easy
Correct Answer: n-type
Explanation:
Introduction / Context:
Knowing which carriers are majority and which are minority is crucial for understanding diode behavior, transistor action, and recombination processes. This question probes identification of minority carriers for a common doping type.
Given Data / Assumptions:
Concept / Approach:
In n-type material, donor impurities add electrons, making electrons the majority carriers and holes the minority carriers. In p-type material, acceptor impurities create holes as majority carriers, making electrons the minority carriers. Intrinsic material has equal concentrations of electrons and holes.
Step-by-Step Solution:
Step 1: Identify n-type doping adds electrons as majority carriers.Step 2: Recognize that the other carrier type (holes) becomes the minority.Step 3: Conclude that holes are minority carriers in n-type semiconductors.
Verification / Alternative check:
Position of the Fermi level near the conduction band in n-type material reflects higher electron concentration and lower hole concentration, consistent with holes as minority carriers.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing majority and minority roles between n-type and p-type, or overlooking that illumination or injection can temporarily change populations; here we assume normal equilibrium.
Final Answer:
n-type.
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