A transistor has collector current I_C = 10 mA and base current I_B = 40 mA. Compute the DC current gain β = I_C / I_B and identify the correct option.

Difficulty: Easy

Correct Answer: None of the above

Explanation:


Introduction / Context:
DC current gain for a BJT in common-emitter configuration is β = I_C / I_B. It is dimensionless, because both I_C and I_B are currents. This question checks unit awareness and the ability to compute β directly from given currents.


Given Data / Assumptions:

  • I_C = 10 mA.
  • I_B = 40 mA (notably large for a base current, but we use it as stated).
  • β is defined as the ratio of these currents and therefore has no unit.


Concept / Approach:

  • Compute β = I_C / I_B.
  • Ensure consistent units (both in mA), and remember β is unitless.
  • Compare the computed numeric value with the provided options and check units/formatting.


Step-by-Step Solution:

Write β = I_C / I_B.Substitute: β = 10 mA / 40 mA = 0.25.β is dimensionless; none of the listed options present '0.25' as a unitless number.


Verification / Alternative check:

Convert both currents to amperes: 0.010 A / 0.040 A = 0.25 (same result). Units cancel out, confirming unitless β.


Why Other Options Are Wrong:

  • 250 μA, 350 μA, 0.25 μA, 300 μA: These include current units and therefore do not represent a unitless gain. Numerically they also do not equal 0.25 as a pure ratio.
  • None of the above: Correct, because the proper answer is the dimensionless value β = 0.25, not a current in microamperes.


Common Pitfalls:

  • Treating β as if it had units (e.g., confusing it with a current magnitude).
  • Mishandling unit conversions between mA and A.


Final Answer:

None of the above (β = 0.25, dimensionless)

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