An electromagnet has 1000 turns (N = 1000). What current is required to produce an mmf of 100 ampere-turns (NI = 100 At)?

Difficulty: Easy

Correct Answer: 0.1 A

Explanation:


Introduction / Context:
Magnetomotive force (mmf) quantifies the 'driving force' for magnetic flux in a magnetic circuit, analogous to emf in electrical circuits. The basic relation is mmf = N * I (ampere-turns). This question reinforces direct proportionality among mmf, turns, and current.


Given Data / Assumptions:

  • Number of turns N = 1000.
  • Required mmf NI = 100 ampere-turns.
  • Core properties and reluctance are irrelevant for computing current from mmf.


Concept / Approach:

  • Use mmf formula: NI = N * I.
  • Solve for I: I = NI / N.


Step-by-Step Solution:

Write formula: NI = N * I.Substitute values: 100 = 1000 * I.Compute: I = 100 / 1000 = 0.1 A.


Verification / Alternative check:

Scale reasoning: If 1000 turns produce 100 At at 0.1 A, then 1 A would give 1000 At; linear scaling confirms correctness.


Why Other Options Are Wrong:

  • 10 A and 100 A: Would produce 10,000 At and 100,000 At respectively, far above 100 At.
  • 1000 A: Physically unrealistic for small coils; would give 1,000,000 At.
  • None of the above: Incorrect because 0.1 A satisfies the requirement.


Common Pitfalls:

  • Confusing ampere-turns with amperes; mmf depends on both current and turns.
  • Overlooking simple division when rearranging NI = N * I.


Final Answer:

0.1 A

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