Difficulty: Easy
Correct Answer: increased at the centre of the beam
Explanation:
Introduction / Context:
Shear force is highest near the supports and lowest at midspan for a simply supported beam with uniformly distributed load. Stirrups resist shear; therefore, their spacing should reflect the shear force diagram rather than remain constant along the length.
Given Data / Assumptions:
Concept / Approach:
Nominal shear stress v = V / (b d) is largest near supports because V is maximum there. To maintain capacity and economy, stirrup spacing is closer (smaller) where shear is high and can be relaxed (larger spacing) where shear is lower, i.e., towards midspan.
Step-by-Step Reasoning:
Plot shear diagram: V_max at supports; V = 0 at midspan.Detail stirrups with minimum spacing near supports, increasing spacing towards the centre.Comply with code minimum and maximum spacing limits in all regions.
Verification / Alternative check:
Running a shear check at critical sections confirms that the most demanding spacing is near supports. Midspan checks usually govern minimum code stirrup provisions only.
Why Other Options Are Wrong:
Constant spacing ignores varying shear.Decreasing spacing towards centre or increasing at ends contradicts the shear distribution.Option e is not a recognized pattern for UDL on simple spans.
Common Pitfalls:
Final Answer:
increased at the centre of the beam
Discussion & Comments