Lap splicing in compression members: The lap length shall not be less than bar_dia * (permissible_stress / (5 * bond_stress)) or which minimum value expressed in bar diameters, whichever is greater?

Difficulty: Easy

Correct Answer: 24 bar diameters

Explanation:


Introduction / Context:
Lap splices in compression must safely transfer force between bars through bond with concrete. Codes specify a calculated lap length and also a minimum bar diameter multiple to cover variability in workmanship and conditions.


Given Data / Assumptions:

  • Compression member with lapped longitudinal bars.
  • Design stresses and bond stresses per standard practice.
  • Requirement: adopt the larger of calculated or minimum lap.


Concept / Approach:
The calculated lap uses permissible stress and bond stress values; however, a minimum of 24φ (φ = bar diameter) is typically specified for compression laps to ensure adequate embedment and confinement length even when calculated values are small.


Step-by-Step Solution:
Compute L_calc = φ * (permissible_stress / (5 * bond_stress)).Compare with L_min = 24φ.Provide lap length = max(L_calc, 24φ) within a zone of adequate transverse reinforcement.


Verification / Alternative check:
Confinement via closer ties in splice regions enhances bond behavior; design guides consistently adopt 24φ as the baseline for compression laps in normal conditions.


Why Other Options Are Wrong:

  • 12φ and 18φ: usually insufficient for reliable compression splices.
  • 30φ or 36φ: conservative but not the commonly mandated minimum for compression laps in ordinary conditions.


Common Pitfalls:
Placing splices at highly stressed sections, inadequate tie spacing, and ignoring cover limitations which reduce bond effectiveness.


Final Answer:
24 bar diameters.

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