Shear capacity check in beams: If the computed nominal shear stress in a reinforced concrete beam exceeds what value, must the beam dimensions be revised (rather than relying only on stirrups)?
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A10 kg/cm2
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B15 kg/cm2
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C20 kg/cm2
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D25 kg/cm2
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E30 kg/cm2
Answer
Correct Answer: 20 kg/cm2
Explanation
Introduction / Context:
Beam design checks nominal shear stress (tau_v) against limits for concrete. Beyond certain thresholds, increasing only shear reinforcement is insufficient; section dimensions must be revised to keep stresses within code bounds.
Given Data / Assumptions:
- Nominal shear stress in an RC beam computed from V / (b * d).
- Old-style units (kg/cm2) often used in competitive exams.
- Typical code limits imply a practical upper bound near 2 N/mm2 (~20 kg/cm2) for concrete under shear before section revision is mandatory.
Concept / Approach:
If tau_v exceeds permissible concrete shear stress (including max with shear reinforcement), codes direct either increasing section size (b or d) or reducing shear demand. A common exam convention flags 20 kg/cm2 as a change-of-dimensions trigger.
Step-by-Step Solution:
Compute tau_v = V / (b * d).Compare with permissible values; if tau_v > ~20 kg/cm2, section dimensions must be revised.Hence, select 20 kg/cm2 as the threshold choice provided.Verification / Alternative check:
Converting 20 kg/cm2 ≈ 2 N/mm2 aligns with familiar upper bounds in many design charts for concrete shear capacity.
Why Other Options Are Wrong:
- 10–15 kg/cm2: Conservative but not the typical exam threshold.
- 25–30 kg/cm2: Too high; risks crushing of web and brittle shear failure.
Common Pitfalls:
- Mistaking allowable shear with design shear carried by stirrups alone; both concrete and steel contributions are bounded.
Final Answer:
20 kg/cm2