Wall shear distribution in fully developed laminar pipe flow: For a viscous fluid in a circular pipe, where is the shear stress magnitude maximum across the cross-section?

Difficulty: Easy

Correct Answer: Maximum at the inner wall (pipe surface)

Explanation:


Introduction / Context:

Understanding shear stress distribution is crucial for estimating friction losses and wall stresses in internal flows. In steady, fully developed laminar flow through a circular pipe, velocity is parabolic and shear stress varies linearly from the centre to the wall.


Given Data / Assumptions:

  • Newtonian fluid; steady, incompressible, fully developed laminar flow.
  • No slip at the wall; axisymmetric conditions.


Concept / Approach:

From the momentum balance, shear stress τ(r) varies with radius r as τ(r) = −(dp/dx) * r / 2, where dp/dx is the (negative) pressure gradient. Thus, τ increases linearly with r, reaching zero at the centre (r = 0) and maximum at the pipe wall (r = R).


Step-by-Step Solution:

Write τ(r) = −(dp/dx) * r / 2.At r = 0 (centre), τ = 0 → no shear at the centre.At r = R (wall), τ_w = −(dp/dx) * R / 2 → maximum magnitude.


Verification / Alternative check:

The parabolic velocity profile v(r) = v_max * (1 − (r/R)^2) has derivative dv/dr proportional to −r, which is largest in magnitude at the wall, consistent with τ = μ dv/dr being maximum there.


Why Other Options Are Wrong:

  • Uniform shear contradicts the linear τ(r) dependence on r.
  • Maximum at centreline is incorrect; τ(0) = 0.
  • Zero at wall (no-slip means zero velocity, not zero shear).


Common Pitfalls:

  • Confusing velocity (zero at wall) with shear stress (maximum at wall).


Final Answer:

Maximum at the inner wall (pipe surface)

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