Most economical trapezoidal channel section — identifying equivalent criteria: Which of the following conditions are satisfied by a hydraulically most economical trapezoidal open-channel section?

Difficulty: Medium

Correct Answer: All of these

Explanation:


Introduction / Context:
The “most economical” (best hydraulic) section minimizes wetted perimeter for a given area, thereby maximizing discharge for a given slope and roughness (or minimizing energy loss). For trapezoidal channels, several geometric conditions are equivalent indicators of this optimum shape.


Given Data / Assumptions:

  • Uniform, steady, open-channel flow.
  • Trapezoidal cross-section with base width b, side slope m:1, and depth y.
  • Optimization under constant area and slope (Manning/Chezy framework).


Concept / Approach:

For the most economical trapezoid, the condition is that the hydraulic radius R = A/P is maximized. This leads to canonical geometric results that can be expressed in multiple equivalent forms, including relationships among top width, side lengths, and inscribed semicircle tangency to the wetted boundary.


Step-by-Step Solution:

Start from optimum condition: d(P)/d(variable) = 0 at fixed A or use calculus of variations.Obtain standard results: half of top width equals sloping side length; side slopes meet the base so that the wetted perimeter is minimized.Show hydraulic mean depth R equals y/2 at optimum, implying efficient conveyance.Geometric construction: semicircle with diameter as top width tangent to wetted boundary confirms symmetry of distances.


Verification / Alternative check:

Textbook derivations using Chezy or Manning demonstrate identical optimum conditions; numerical examples confirm lower P for the same A at the optimum.


Why Other Options Are Wrong:

Here, (a), (b), and (c) are each true descriptors; thus selecting only one would be incomplete. The correct comprehensive choice is (d).


Common Pitfalls:

Confusing the most economical rectangle (b = 2y) with trapezoid conditions; overlooking that several geometric tests are equivalent at optimum.


Final Answer:

All of these

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