Critical depth in open-channel flow (rectangular channel): which expression gives the critical depth h_c in terms of discharge per unit width q?

Difficulty: Easy

Correct Answer: h_c = ( q^2 / g )^(1/3)

Explanation:


Introduction / Context:
Critical depth is the depth at which the specific energy is minimum for a given discharge in an open channel. For a rectangular channel, it provides a convenient criterion for transitions between subcritical (tranquil) and supercritical (torrential) flow and is widely used in the design of flumes and spillways.



Given Data / Assumptions:

  • Rectangular channel of unit width; discharge per unit width q = Q / b.
  • Gravitational acceleration g constant.
  • Frictional losses neglected in the local specific energy analysis.


Concept / Approach:

Specific energy E for a rectangular channel is E = h + q^2/(2 * g * h^2). The critical depth h_c occurs when dE/dh = 0, giving the condition Fr = 1 (q^2 = g * h_c^3), from which h_c is obtained.



Step-by-Step Solution:

Write E(h) = h + q^2 / (2 g h^2).Differentiate and set dE/dh = 0 → 1 − q^2 / (g h^3) = 0.Solve for h: g * h^3 = q^2.Hence h_c = ( q^2 / g )^(1/3).


Verification / Alternative check (if short method exists):

Use Froude number for rectangular section: Fr = v / sqrt(g * h) with v = q / h. Setting Fr = 1 → (q / h) = sqrt(g * h) → q^2 = g * h^3, identical result.


Why Other Options Are Wrong:

They invert or misapply powers of q and g, or confuse dimensional consistency (depth must scale as (q^2/g)^(1/3)).


Common Pitfalls (misconceptions, mistakes):

Forgetting that q is discharge per unit width, not total discharge; misusing Froude number definition.


Final Answer:

h_c = ( q^2 / g )^(1/3)

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