Difficulty: Medium
Correct Answer: 750 m
Explanation:
Introduction / Context:
Overtaking sight distance (OSD) on two-lane two-way highways ensures that a driver can pass a slower vehicle and return to the lane without conflict with an opposing vehicle. OSD grows rapidly with speed and depends on available acceleration.
Given Data / Assumptions:
Concept / Approach:
OSD is the sum of distances: OSD = d_react + d_overtake + d_clear. With higher V and modest a, the overtaking time is relatively long, and the clearance portion for the opposing vehicle adds substantially to the total. For V around 100 km/h, IRC tables and derived computations place OSD in the ~700–750 m range.
Step-by-Step Solution:
Convert speed: V = 27.78 m/s.Approximate overtaking time using kinematics with acceleration a and speed differential typical of design practice (leading to 10–12 s maneuver time).Compute distance travelled by the overtaking vehicle during decision and maneuver plus the distance covered by the opposing vehicle during the critical interval.Sum components → OSD ≈ 700–750 m; adopt the conservative value given.
Verification / Alternative check:
IRC guideline values for 100 km/h corroborate an OSD of roughly three-quarters of a kilometre. Lower figures (300–470 m) align with lower design speeds (60–80 km/h).
Why Other Options Are Wrong:
300–320 m: Suitable for ~60 km/h. 470–560 m: Near values for ~80–90 km/h. 750 m matches 100 km/h design requirements.
Common Pitfalls:
Final Answer:
750 m
Discussion & Comments