Difficulty: Medium
Correct Answer: D = (q / γ) * ((1 - sin φ) / (1 + sin φ))^2
Explanation:
Introduction / Context:
Rankine's depth of foundation formula provides a minimum embedment to prevent shear failure and ensure the overburden confining pressure mobilizes adequate passive resistance. It relates the foundation depth to soil strength parameters in a simple closed form widely used for preliminary sizing.
Given Data / Assumptions:
Concept / Approach:
Rankine's active earth pressure coefficient K_a = ((1 − sin φ) / (1 + sin φ))^2. The classic embedment relation may be written as D = (q / (γ K_a)), which rearranges to D = (q / γ) * ((1 − sin φ) / (1 + sin φ))^2. This ensures that vertical overburden at the base provides the confining stress consistent with allowable pressure.
Step-by-Step Solution:
Compute K_a = ((1 − sin φ) / (1 + sin φ))^2.Use D = (q / (γ K_a)).Substitute K_a: D = (q / γ) * ((1 − sin φ) / (1 + sin φ))^2.Thus, option (a) matches Rankine's expression.
Verification / Alternative check:
For φ = 0°, K_a = 1, giving D = q / γ, which is dimensionally consistent and physically reasonable for purely frictionless soil in this simplified context.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing K_a (active) with K_p (passive); omitting the square on ((1 − sin φ)/(1 + sin φ)).
Final Answer:
D = (q / γ) * ((1 - sin φ) / (1 + sin φ))^2
Discussion & Comments