Laminar loss in a circular pipe: For a viscous liquid flowing at mean velocity v through a circular pipe of length L and diameter d, the head loss due to viscous effects is approximately what?

Difficulty: Easy

Correct Answer: h_f = 32 μ v L / (ρ g d^2)

Explanation:


Introduction / Context:

In fully developed laminar flow inside a circular pipe, the Hagen–Poiseuille law governs the pressure drop and head loss. Recognizing the correct dependence on viscosity μ, length L, diameter d, and mean velocity v is important for microfluidics, lubrication problems, and low-Reynolds-number flows.


Given Data / Assumptions:

  • Steady, incompressible, Newtonian fluid.
  • Fully developed laminar flow (Re < 2100 typically).
  • Gravity head g included to convert pressure loss to head loss.


Concept / Approach:

Start from Darcy–Weisbach form h_f = f (L/d) * v^2/(2g) with laminar friction factor f = 64/Re, where Re = ρ v d / μ. Substituting f and simplifying yields the laminar head-loss expression directly proportional to μ, v, and L, and inversely proportional to d^2.


Step-by-Step Solution:

Take f = 64 / Re = 64 μ / (ρ v d).Insert into h_f: h_f = (64 μ / (ρ v d)) * (L/d) * v^2/(2g).Simplify: h_f = (64 μ L v) / (ρ 2 g d^2) = 32 μ v L / (ρ g d^2).


Verification / Alternative check:

Using the Hagen–Poiseuille equation Δp = 32 μ v L / d^2 also leads to the same head loss since h_f = Δp/(ρ g).


Why Other Options Are Wrong:

  • Option A is the general Darcy–Weisbach form but not a closed form for laminar flow unless f is replaced appropriately.
  • Option C has incorrect diameter dependence.
  • Option D is dimensionally inconsistent.


Common Pitfalls:

  • Confusing mean velocity v with centerline velocity (which is 2v in laminar flow).


Final Answer:

h_f = 32 μ v L / (ρ g d^2)

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