Minimum wall thickness of metallic storage vessels depends on what variables? Choose the most complete statement.
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AUltimate tensile strength (or yield point) and operating temperature
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BOperating pressure and welding/joint efficiency
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CVessel diameter
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DAll (a), (b) and (c)
Answer
Correct Answer: All (a), (b) and (c)
Explanation
Introduction / Context:Determining wall thickness for pressure-containing vessels and storage tanks requires balancing strength, geometry, and service conditions. Codes provide formulas that include material properties, pressure, diameter, and joint efficiency, plus allowances.
Given Data / Assumptions:
- Metallic cylindrical/spherical vessels under internal pressure.
- Design per recognized codes with joint efficiency factors.
- Temperature limits affect allowable stresses.
Concept / Approach:For thin shells, fundamental hoop-stress relationships lead to thickness proportional to pressure * radius divided by allowable stress, modified by joint efficiency. Allowable stress derives from material yield/ultimate strength and design temperature. Geometry (diameter) sets radius, directly impacting required thickness.
Step-by-Step Solution:Material property/temperature → allowable stress S(T).Pressure P and diameter D → hoop stress ~ P * D / (2 t).Joint efficiency E reduces effective strength; thickness scales by 1/E.Thus, thickness = f(P, D, S(T), E), confirming all listed variables matter.
Verification / Alternative check:Design equations from pressure vessel codes explicitly include P, D (or radius), S (function of material and temperature), and weld efficiency; corrosion and mill tolerances add further allowances.
Why Other Options Are Wrong:Any single-variable choice ignores interacting effects in code formulas and real design.
Common Pitfalls:Neglecting temperature derating; forgetting joint efficiency for welded seams; omitting corrosion allowance and tolerances.
Final Answer:All (a), (b) and (c)