Difficulty: Easy
Correct Answer: Pyrophosphoric acid (H₄P₂O₇)
Explanation:
Introduction:
Phosphoric acids undergo stepwise condensation upon heating, forming P–O–P linkages and releasing water. Recognizing which species forms at a given temperature is important in fertilizer and phosphate processing.
Given Data / Assumptions:
Concept / Approach:
Upon heating, two molecules of H3PO4 condense: 2 H3PO4 → H4P2O7 + H2O, giving pyrophosphoric (diphosphoric) acid. At still higher temperatures and with prolonged dehydration, polyphosphoric and finally metaphosphoric acids (general formula HPO3)n can form. But near 250°C, the predominant product is H4P2O7.
Step-by-Step Solution:
Write the condensation: 2 H3PO4 → H4P2O7 + H2O.Match temperature regime: ≈200–300°C favors diphosphoric acid.Conclude that pyrophosphoric acid is produced.
Verification / Alternative check:
Process texts on phosphate fertilizers describe controlled dehydration steps, with pyrophosphate formation preceding metaphosphate formation at higher temperature.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing orthophosphoric dehydration series; mixing up phosphoric (H3PO4) and phosphorous (H3PO3) acids.
Final Answer:
Pyrophosphoric acid (H₄P₂O₇)
Discussion & Comments