Temperature sensitivity rule of thumb If the rate of a chemical reaction doubles for every 10 °C rise, by what factor does the rate increase when temperature is raised from 30 °C to 70 °C?
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A8
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B12
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C16
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D32
Answer
Correct Answer: 16
Explanation
Introduction / Context:A common engineering rule of thumb states that many reaction rates approximately double for each 10 °C temperature increase. This is a practical approximation derived from Arrhenius behavior for moderate temperature ranges.
Given Data / Assumptions:
- Rate doubles for every ΔT = 10 °C.
- Temperature change: 30 °C to 70 °C (ΔT = 40 °C).
Concept / Approach:Apply the doubling rule in discrete steps equal to 10 °C increments. Each 10 °C step multiplies the rate by 2. For 40 °C total increase, there are 4 such steps.
Step-by-Step Solution:Number of 10 °C steps = (70 − 30)/10 = 4.Overall multiplicative factor = 2^4 = 16.Therefore, rate at 70 °C ≈ 16 times the rate at 30 °C.
Verification / Alternative check:Arrhenius equation k = A exp(−Ea/RT) shows exponential sensitivity to 1/T; the doubling rule is an empirical simplification consistent with moderate Ea values over modest ranges.
Why Other Options Are Wrong:
- 8 corresponds to three doublings (30 to 60 °C).
- 12 is not a power-of-two doubling outcome.
- 32 would require five doublings (30 to 80 °C).
Common Pitfalls:
- Counting the number of temperature intervals incorrectly or including the starting temperature as a “step.”
Final Answer:16