Difficulty: Easy
Correct Answer: Two
Explanation:
Introduction / Context:
This problem checks your ability to manipulate letters inside given words and then to apply the concept of vowels and consonants. Such questions are very typical in alphabet test and verbal reasoning sections, which assess attention to detail and speed of basic mental operations.
Given Data / Assumptions:
Concept / Approach:
The approach is to transform each word according to the rule and then count vowels in each new word. The next alphabet after a given letter means moving one step forward in the sequence A, B, C, D, and so on. Once each new word is obtained, simply scan each letter and count how many are vowels, then tally the words that have exactly two vowels.
Step-by-Step Solution:
Verification / Alternative check:
List the transformed words again: AOD, FPR, TIE, BJG and SVM. Mark vowels clearly. AOD has A and O as vowels, TIE has I and E as vowels, the remaining three words have no vowel at all. Therefore, exactly two words meet the condition of having two vowels. This confirms the count without any doubt.
Why Other Options Are Wrong:
Common Pitfalls:
Students sometimes misidentify Y as a vowel in such questions, but here Y does not appear. Another frequent mistake is to change the wrong letter position instead of always changing the second letter. Also, careless reading can lead to counting total vowels across all words rather than the number of words that have exactly two vowels. Reading the question carefully and working word by word avoids these issues.
Final Answer:
The number of words that contain exactly two vowels after the specified change is Two.
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