Consider the following series of three letter groups based on the English alphabet: CEA, JLH, QSO. What should be the next group of three letters in this alphabet series so that the pattern continues correctly?

Difficulty: Medium

Correct Answer: XZV

Explanation:


Introduction / Context:
This is a letter series question in which groups of three alphabets follow a specific pattern. The given groups are CEA, JLH and QSO, and we need to identify the next group. Such questions appear frequently in alphabet test sections and measure your ability to observe regular jumps and consistent numeric relationships between alphabet positions.


Given Data / Assumptions:

    The given groups are CEA, JLH and QSO.
    Each group contains three letters, which we can treat as first, second and third positions in the group.
    The English alphabet is considered in standard A to Z order for all numeric conversions.
    The next required group must continue exactly the same pattern seen in the given three groups.


Concept / Approach:
The usual technique is to convert each letter to its position in the alphabet and then study how the positions change from one group to the next. If all first letters follow a simple pattern, all second letters often follow the same pattern, and the same is true for third letters. Here, we look at the progression from C to J to Q for first letters, from E to L to S for second letters, and from A to H to O for third letters. If each sequence increases by a constant number, we can predict the next letter in each sequence.


Step-by-Step Solution:

Step 1: Convert the first letters: C is 3, J is 10 and Q is 17. Each time we add 7 (3 + 7 = 10 and 10 + 7 = 17). Step 2: Adding another 7 gives 17 + 7 = 24, which corresponds to X as the next first letter. Step 3: Convert the second letters: E is 5, L is 12 and S is 19. Again, we keep adding 7 (5 + 7 = 12 and 12 + 7 = 19). Step 4: Add 7 once more to get 19 + 7 = 26, which corresponds to Z as the next second letter. Step 5: Convert the third letters: A is 1, H is 8 and O is 15, which again follow a +7 pattern. Adding 7 to 15 gives 22, corresponding to V. Thus the next group is XZV.


Verification / Alternative check:
You can verify the pattern by listing the numeric sequences separately: for first letters 3, 10, 17, 24; for second letters 5, 12, 19, 26; for third letters 1, 8, 15, 22. Each is clearly an arithmetic progression with common difference 7. The letters corresponding to 24, 26 and 22 are X, Z and V, respectively. None of the other options matches this triple result, which confirms XZV as the only correct continuation of the series.


Why Other Options Are Wrong:

    WYU gives first and second letters that do not fit the +7 arithmetic pattern for the numeric sequence of letters and therefore breaks the consistent rule.
    UXW partly matches in feel but its individual letters do not match the exact positions computed by adding seven each time, so it is inconsistent with the established pattern.
    WXV correctly uses V as the third letter but the first and second letters are not 24 and 26, so it does not fully agree with the numeric progression observed.


Common Pitfalls:
Many students only look at one position inside the groups and choose an option that partially fits, ignoring that all three letters must follow the same rule. Others treat the letters visually rather than numerically, which makes it easy to miss the constant difference of seven. Always convert letter sequences into number sequences so that arithmetic patterns become obvious and easier to verify.


Final Answer:
The correct next group of three letters in the series CEA, JLH, QSO is XZV.

More Questions from Alphabet Test

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion