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Given the following network range 192.168.0.0/24. We want minimum 50 hosts on each of the available subnets. What will be the subnet mask?

Correct Answer: /26

Explanation:

Explanation: 50 hosts require 6 bits of the last octet giving us 64 -2 = 62 possible hosts this satisfies our requirement and leaves us 2 bits over for the subnets. The default mask is /24 or 255.255.255.0 adding the 2 bits for the subnets it becomes 255.255.255.192 or /26


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