Difficulty: Easy
Correct Answer: a = sqrt(K / ρ)
Explanation:
Introduction:
The propagation speed of small pressure disturbances in a fluid (acoustic speed) is a key parameter in water-hammer analysis and compressible-flow acoustics. It depends on the compressibility of the medium (bulk modulus) and its density.
Given Data / Assumptions:
Concept / Approach:
The classical derivation from continuity and momentum linearized about a uniform state yields the wave equation with speed a satisfying a^2 = K / ρ, where K = −V * (dP/dV) is the bulk modulus. Thus a = sqrt(K / ρ). In liquid–pipe systems, pipe wall elasticity can be incorporated by using an effective modulus that reduces a below the pure-fluid value.
Step-by-Step Solution:
Verification / Alternative check:
For water with K ≈ 2.2 * 10^9 Pa and ρ ≈ 1000 kg/m^3, a ≈ sqrt(2.2 * 10^6) ≈ 1483 m/s—consistent with tabulated sound speeds in water.
Why Other Options Are Wrong:
K / ρ, ρ / K, K * ρ: Miss the necessary square root or have wrong dimensions.sqrt(ρ / K): Inverts the ratio; would give unphysical behavior.
Common Pitfalls:
Forgetting to include pipe wall elasticity in water-hammer problems; the effective a can drop substantially in flexible pipes.
Final Answer:
a = sqrt(K / ρ)
Discussion & Comments