Difficulty: Easy
Correct Answer: 2.5%
Explanation:
Introduction:
Discharge over notches and weirs is a power function of head. Understanding error propagation helps prioritize measurement accuracy for key variables.
Given Data / Assumptions:
Concept / Approach:
For Q ∝ H^n, the relative error relation is dQ/Q = n * dH/H for small perturbations. For a V-notch, n = 5/2 = 2.5, which amplifies head measurement errors by a factor of 2.5.
Step-by-Step Solution:
1) Write Q = K * H^(5/2).2) Take logarithms and differentiate: dQ/Q = (5/2) * dH/H.3) With dH/H = 0.01, compute dQ/Q = 2.5 * 0.01 = 0.025 = 2.5%.4) Hence, a 1% head error gives about 2.5% discharge error.
Verification / Alternative check:
A rectangular notch has Q ∝ H^(3/2), so a 1% head error would yield ~1.5% Q error—smaller than the triangular notch case, consistent with the higher exponent for V-notches.
Why Other Options Are Wrong:
Common Pitfalls:
Applying rectangular-notch exponents to V-notches; ignoring that error propagation assumes small percentage errors.
Final Answer:
2.5%
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