Difficulty: Easy
Correct Answer: 85
Explanation:
Introduction:
Catalytic reforming upgrades low-octane naphtha into high-octane reformate and produces hydrogen. Knowing typical reformate yield helps in refinery LP planning, hydrogen balance, and octane pool forecasting.
Given Data / Assumptions:
Concept / Approach:
Reforming involves dehydrogenation, isomerisation, cyclization, and dehydrocyclization. These steps generate hydrogen and some light ends (C1–C4), so the liquid reformate yield is less than 100% of feed. A typical planning value lies around the mid-80s wt%, subject to severity and feed composition. Hence, 85 wt% is a sensible representative figure.
Step-by-Step Solution:
1) Recognize that reforming consumes part of the feed as light gases and H2.2) Recall planning heuristics: reformate yields ~80–90 wt% depending on severity and feed paraffinicity.3) Choose 85 as a representative middle value.
Verification / Alternative check:
Licensor and textbook examples often show yields near 83–88 wt% for standard severities; severe reforming for high octane typically lowers yield slightly.
Why Other Options Are Wrong:
65 or 50: Too low for typical operation; would imply excessive cracking.98: Unrealistically high given H2 and light gas formation.72: Low relative to mainstream planning figures.
Common Pitfalls:
Assuming reforming is purely rearrangement with no yield loss; dehydrogenation and side cracking inevitably produce off-gas.
Final Answer:
85
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