Difficulty: Easy
Correct Answer: two zeros
Explanation:
Introduction / Context:
Resistor colour codes encode the nominal resistance and tolerance. In a 4-band scheme, the first two bands give significant digits, the third band is the multiplier (a power of ten), and the fourth band is tolerance.
Given Data / Assumptions:
Concept / Approach:
The colour-to-number mapping is: black 0, brown 1, red 2, orange 3, yellow 4, green 5, blue 6, violet 7, grey 8, white 9. As a multiplier, the third band represents 10^(colour number). Red corresponds to 10^2, meaning “add two zeros” after the first two significant digits.
Step-by-Step Solution:
Map red → 2.Multiplier = 10^2.10^2 means two trailing zeros when writing the resistance value.Therefore, the third red band indicates “two zeros”.
Verification / Alternative check:
Example: yellow-violet-red-gold → 47 × 10^2 = 4.7 kΩ ±5%.
Why Other Options Are Wrong:
(b) “three zeros” corresponds to orange (10^3); (c) 0.01 and (d) 0.1 are multipliers for silver (10^−2) and gold (10^−1) respectively, not red.
Common Pitfalls:
Reading from the wrong end; confusing 5-band code (three significant digits) with 4-band code.
Final Answer:
two zeros
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