Capacitors in parallel — to compute total capacitance of capacitors connected in parallel, sum the individual capacitances (CT = C1 + C2 + …). Is this statement correct?

Difficulty: Easy

Correct Answer: Correct

Explanation:


Introduction / Context:
Capacitor combining rules mirror resistor combining rules but with roles swapped: capacitances add in parallel and combine reciprocally in series. This property is widely used to realize non-standard values and increase energy storage.


Given Data / Assumptions:

  • Capacitors are connected node-to-node (parallel).
  • Ideal components (no leakage or parasitics) for the rule statement.


Concept / Approach:
In parallel, plates effectively increase total plate area while maintaining the same voltage across each capacitor, so charge adds linearly: Q_total = ΣCi * V. Since CT = Q_total / V, we get CT = ΣCi.


Step-by-Step Solution:

1) Write Qi = Ci * V for each branch (same V in parallel).2) Sum charges: Q_total = ΣCi * V.3) Define CT by Q_total = CT * V → CT = ΣCi.4) Conclude the statement is correct.


Verification / Alternative check:
Measure with an LCR meter: two capacitors 10 µF // 22 µF ≈ 32 µF (ignoring tolerances).


Why Other Options Are Wrong:

Only identical / only AC / depends on dielectric: the addition rule holds for any values and dielectrics under linear conditions.


Common Pitfalls:
Confusing series and parallel rules; forgetting voltage ratings still apply and should not be exceeded.


Final Answer:
Correct

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