Difficulty: Easy
Correct Answer: an increase in total XC
Explanation:
Introduction / Context:
Knowing how reactances combine helps anticipate impedance and voltage distribution in AC networks. For series networks, impedances simply add as complex quantities.
Given Data / Assumptions:
Concept / Approach:
Impedances in series add: Z_total = Σ Zi. For purely capacitive branches, Zi = -jXci. Thus Xc,total = Xc1 + Xc2 + ... . Adding positive magnitudes yields a larger total reactance magnitude, meaning greater opposition to AC current.
Step-by-Step Solution:
Write each branch impedance: Zi = -jXci.Series sum: Z_total = -j(Xc1 + Xc2 + ...).Magnitude increases with each additional series reactance: |Z_total| = Xc1 + Xc2 + ... .Therefore, the total capacitive reactance increases when connected in series.
Verification / Alternative check:
Duality with resistors: resistances in series also add. In contrast, capacitors themselves (as components) in series reduce equivalent capacitance, but their individual reactances at a given frequency still add.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
an increase in total XC
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