Difficulty: Medium
Correct Answer: 1.31 mA
Explanation:
Introduction:
In a parallel RC circuit driven by a sinusoidal source, the resistor current and the capacitor current are not in phase. The resistor branch current is in phase with voltage, while the capacitor branch current leads the voltage by 90 degrees. The total source current is therefore the vector (phasor) sum of these orthogonal branch currents, not the arithmetic sum.
Given Data / Assumptions:
Concept / Approach:
For the resistor branch: I_R = V / R. For the capacitor branch: I_C = V / X_C, where X_C = 1 / (2 * π * f * C). Because the two currents are 90 degrees apart, the resultant magnitude is I_total = sqrt(I_R^2 + I_C^2).
Step-by-Step Solution:
Compute capacitive reactance: X_C = 1 / (2 * π * f * C)2 * π * f * C = 2 * π * 5e6 * 27e-12 ≈ 8.482e-4X_C ≈ 1 / 8.482e-4 ≈ 1179 ΩResistor current (rms): I_R = V / R = 1 / 1000 = 0.001 A = 1.0 mACapacitor current (rms): I_C = V / X_C ≈ 1 / 1179 ≈ 0.000848 A = 0.848 mATotal current magnitude: I_total = sqrt(I_R^2 + I_C^2) ≈ sqrt((1.0 mA)^2 + (0.848 mA)^2)I_total ≈ sqrt(1 + 0.719) mA ≈ sqrt(1.719) mA ≈ 1.31 mA
Verification / Alternative check:
Because branches are in parallel, voltages are equal. Orthogonal currents combine by Pythagoras. The computed X_C around 1.18 kΩ at 5 MHz for 27 pF is reasonable and results in I_C slightly less than I_R, so a total just above 1 mA is expected, agreeing with 1.31 mA.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
1.31 mA
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