The capacities of two hemispherical vessels are 6.4 litres and 21.6 litres. The areas of inner curved surfaces of the vessels will be in the ratio of
Aptitude
Volume and Surface Area
Difficulty: Medium
Choose an option
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A\sqrt{2} : \sqrt{3}
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B2 : 3
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C4 : 9
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D16 : 81
Answer
Correct Answer: 4 : 9
Explanation
### Concept & Proportional Scaling of Shapes
For similar 3D shapes, the ratio of their volumes is proportional to the cube of the ratio of their one-dimensional measures (like radius). The ratio of their surface areas is proportional to the square of that same 1D ratio.
$$\frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^3$$
$$\frac{A_1}{A_2} = \left(\frac{r_1}{r_2}\right)^2$$
### Step-by-Step Solution
1. **Find Ratio of Radii:**
$\frac{V_1}{V_2} = \frac{6.4}{21.6} = \frac{64}{216}$
Since $\frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^3$, we have:
$\left(\frac{r_1}{r_2}\right)^3 = \frac{64}{216}$
Taking the cube root: $\frac{r_1}{r_2} = \frac{\sqrt[3]{64}}{\sqrt[3]{216}} = \frac{4}{6} = \frac{2}{3}$.
2. **Find Ratio of Surface Areas:**
The area ratio is the square of the radius ratio.
$\frac{A_1}{A_2} = \left(\frac{r_1}{r_2}\right)^2 = \left(\frac{2}{3}\right)^2$
$\frac{A_1}{A_2} = \frac{4}{9}$
### Exam Strategy & Shortcut
Recognize $6.4$ and $21.6$ as decimals hiding perfect cubes ($64 = 4^3$ and $216 = 6^3$). Immediately convert the volume ratio $4^3 : 6^3$ to the 1D ratio $4 : 6 = 2 : 3$, and square it for the area ratio to get $4 : 9$.
### Common Pitfall
A common pitfall is stopping at the linear ratio ($2 : 3$) or cubing the squares incorrectly. Always verify which ratio (1D, 2D, or 3D) is being requested.
### Final Answer
Therefore, the correct answer is **4 : 9**.