Capacity of a canal with isosceles trapezium cross-section: Cross-section is an isosceles trapezium, 3 m wide at bottom and 5 m at top, depth 2 m, length 110 m. Find the maximum capacity (in cubic metres).

Introduction / Context:The canal’s capacity equals cross-sectional area times length. The cross-section is a trapezium with known parallel sides and height (depth).

Given Data / Assumptions:

• Bottom width b1 = 3 m; top width b2 = 5 m.
• Depth h = 2 m.
• Length L = 110 m.

Concept / Approach:Area(trapezium) = (1/2) * (b1 + b2) * h. Capacity = Area * L.

Step-by-Step Solution:

Verification / Alternative check:Units: (m^2)*m → m^3, correct.

Why Other Options Are Wrong:1760, 1650, 1056, 990 do not equal 8*110.

Common Pitfalls:Using the average width incorrectly or forgetting to multiply by the length.

Final Answer:880 cubic metres