A rectangle has diagonal 25 cm and breadth (width) 7 cm. Find its perimeter in centimetres.

Introduction / Context:For a rectangle with length L and breadth W, the diagonal d satisfies d^2 = L^2 + W^2. From L, W we obtain the perimeter P = 2(L + W). Here d and W are given, so L follows from Pythagoras.

Given Data / Assumptions:

• d = 25 cm, W = 7 cm.

Concept / Approach:Compute L = √(d^2 − W^2) and then P = 2(L + W).

Step-by-Step Solution:

Verification / Alternative check:Check the triple: 7, 24, 25 is a classic Pythagorean triple. Hence computations are consistent.

Why Other Options Are Wrong:124 and 82 are double-counting or mixing values; 41 is half of 82 and not a valid perimeter given L and W.

Final Answer:62