From a can full of milk, $10$ litres of milk is taken out and replaced with water and this operation is repeated twice. If the capacity of the can is $50$ litres, what is the ratio of water and milk in the can after this operation?
Aptitude
Alligation or Mixture
Difficulty: Medium
Choose an option
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A$2 : 3$
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B$9 : 16$
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C$16 : 9$
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DNone of these
Answer
Correct Answer: None of these
Explanation
### Concept & Successive Replacement
When a fixed quantity of a mixture is repeatedly removed and replaced with water, the amount of the original pure liquid remaining can be calculated using the successive dilution formula.
$$ \text{Final Quantity} = \text{Initial Quantity} \times \left(1 - \frac{\text{Replacement Volume}}{\text{Total Capacity}}\right)^n $$
Where $n$ is the *total* number of times the operation is performed.
### Step-by-Step Solution
* **Given:**
- Initial quantity of milk ($I$) = $50$ liters
- Replacement volume ($R$) = $10$ liters
- The operation is done once, and then "repeated twice", meaning the total number of operations ($n$) is $1 + 2 = 3$.
* **Calculation:**
1. Calculate the final volume of milk left after $3$ operations:
$\text{Final Milk} = 50 \times \left(1 - \frac{10}{50}\right)^3$
$\text{Final Milk} = 50 \times \left(1 - \frac{1}{5}\right)^3$
$\text{Final Milk} = 50 \times \left(\frac{4}{5}\right)^3$
$\text{Final Milk} = 50 \times \frac{64}{125} = 2 \times \frac{64}{5} = \frac{128}{5} = 25.6 \text{ liters}$
2. Calculate the final volume of water in the $50$-liter can:
$\text{Final Water} = \text{Total Capacity} - \text{Final Milk}$
$\text{Final Water} = 50 - 25.6 = 24.4 \text{ liters}$
3. Find the ratio of water to milk:
Ratio = $24.4 : 25.6 = 244 : 256$
4. Simplify the ratio by dividing by $4$:
$61 : 64$
5. The ratio $61 : 64$ is not present in the given options ($2:3$, $9:16$, $16:9$).
### Exam Strategy & Shortcut
Recognize the linguistic traps in dilution problems. Calculate the multiplier $(1 - \frac{10}{50}) = \frac{4}{5}$. If the operation is done $3$ times total, the final milk fraction is $(\frac{4}{5})^3 = \frac{64}{125}$.
Milk = $64$ parts, Water = $(125 - 64) = 61$ parts. Ratio of Water to Milk = $61 : 64$. None of the options match.
### Common Pitfall
A massive trap is misinterpreting the phrase "and this operation is repeated twice" as meaning the operation was performed a *total* of $2$ times. If $n=2$, the final milk fraction is $(\frac{4}{5})^2 = \frac{16}{25}$. The ratio of milk to total is $16:25$, meaning the ratio of Water to Milk is $9:16$, which perfectly matches option (b). However, strict English interpretation of "repeated twice" means $3$ total operations.
### Final Answer
Therefore, the correct answer is **None of these**.