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What will be the output of the following program in 16 bit platform assuming that 1022 is memory address of the string "Hello1" (in Turbo C under DOS)? #include int main() { printf("%u %s\n", &"Hello1", &"Hello2"); return 0; }

1022 Hello2
Hello1 1022
Hello1 Hello2
1022 1022
Error

Correct Answer: 1022 Hello2

Explanation:

In printf("%u %s\n", &"Hello", &"Hello");.

The %u format specifier tells the compiler to print the memory address of the "Hello1".

The %s format specifier tells the compiler to print the string "Hello2".

Hence the output of the program is "1022 Hello2".

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