What will be the output of the program? #include int main() { char str = "CuriousTab"; printf("%s\n", str); return 0; }

Q: What will be the output of the program? #include int main() { char str = "CuriousTab"; printf("%s\n", str); return 0; }

The line char str = "CuriousTab"; generates "Non portable pointer conversion" error. To eliminate the error, we have to change the above line to char *str = "CuriousTab"; (or) char str[] = "CuriousTab"; Then it prints "CuriousTab".

Error
CuriousTab
Base address of str
No output

Correct Answer: Error

Explanation:

The line char str = "CuriousTab"; generates "Non portable pointer conversion" error.

To eliminate the error, we have to change the above line to

char *str = "CuriousTab"; (or) char str[] = "CuriousTab";

Then it prints "CuriousTab".

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