What will be the output of the program? #include int *check(static int, static int); int main() { int *c; c = check(10, 20); printf("%d ", c); return 0; } int *check(static int i, static int j) { int *p, *q; p = &i…

Question

What will be the output of the program? #include<stdio.h>
int *check(static int, static int);

int main()
{
    int *c;
    c = check(10, 20);
    printf("%d
", c);
    return 0;
}
int *check(static int i, static int j)
{
    int *p, *q;
    p = &i…

Accepted Answer

Answer explained in detail.

What will be the output of the program? #include<stdio.h> int check(static int, static int); int main() { int c; c = check(10, 20); printf("%d\n", c); return 0; } int check(static int i, static int j) { int p, *q; p = &i; q = &j; if(i >= 45) return (p); else return (q); }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int *check(static int, static int); int main() { int *c; c = check(10, 20); printf("%d\n", c); return 0; } int *check(static int i, static int j) { int *p, *q; p = &i; q = &j; if(i >= 45) return (p); else return (q); }

Discussion & Comments

What will be the output of the program? #include<stdio.h> int check(static int, static int); int main() { int c; c = check(10, 20); printf("%d\n", c); return 0; } int check(static int i, static int j) { int p, *q; p = &i; q = &j; if(i >= 45) return (p); else return (q); }