What will be the output of the program? #include int main() { int i; i = scanf("%d %d", &i, &i); printf("%d ", i); return 0; }

Q: What will be the output of the program? #include int main() { int i; i = scanf("%d %d", &i, &i); printf("%d\n", i); return 0; }

scanf() returns the number of variables to which you are provding the input. i = scanf("%d %d", &i, &i); Here Scanf() returns 2. So i = 2. printf("%d\n", i); Here it prints 2.

Question

What will be the output of the program? #include<stdio.h>

int main()
{
    int i;
    i = scanf("%d %d", &i, &i);
    printf("%d
", i);
    return 0;
}

Accepted Answer

scanf() returns the number of variables to which you are provding the input. i = scanf("%d %d", &i, &i); Here Scanf() returns 2. So i = 2.

printf("%d ", i); Here it prints 2.

What will be the output of the program? #include<stdio.h> int main() { int i; i = scanf("%d %d", &i, &i); printf("%d\n", i); return 0; }

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