Home » C Programming » Library Functions

What will be the output of the program? #include #include int main() { char dest[] = {97, 97, 0}; char src[] = "aaa"; int i; if((i = memcmp(dest, src, 2))==0) printf("Got it"); else printf("Missed"); return 0; }

Missed
Got it
Error in memcmp statement
None of above

Correct Answer: Got it

Explanation:

memcmp compares the first 2 bytes of the blocks dest and src as unsigned chars. So, the ASCII value of 97 is 'a'.

if((i = memcmp(dest, src, 2))==0) When comparing the array dest and src as unsigned chars, the first 2 bytes are same in both variables.so memcmp returns '0'.
Then, the if(0=0) condition is satisfied. Hence the output is "Got it".

← Previous Question Next Question→

More Questions from Library Functions

What will be the output of the program? #include int main() { int i; i = scanf("%d %d", &i, &i); printf("%d\n", i); return 0; }
What will be the output of the program? #include #include int main() { float i = 2.5; printf("%f, %d", floor(i), ceil(i)); return 0; }
What will function gcvt() do?
What will be the output of the program? #include int main() { int i; i = printf("How r u\n"); i = printf("%d\n", i); printf("%d\n", i); return 0; }
What will be the output of the program? #include int main() { int i; char c; for(i=1; i<=5; i++) { scanf("%c", &c); /* given input is 'b' */ ungetc(c, stdout); printf("%c", c); ungetc(c, stdin); } return 0; }
What will be the output of the program? #include int main() { int i; char c; for(i=1; i<=5; i++) { scanf("%c", &c); /* given input is 'a' */ printf("%c", c); ungetc(c, stdin); } return 0; }
What will be the output of the program? #include #include int main() { char *i = "55.555"; int result1 = 10; float result2 = 11.111; result1 = result1+atoi(i); result2 = result2+atof(i); printf("%d, %f", result1, result2); return 0; }

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion