What will be the output of the program in DOS (Compiler - Turbo C)? #include double i; int main() { (int)(float)(char) i; printf("%d", sizeof((int)(float)(char)i)); return 0; }

Question

What will be the output of the program in DOS (Compiler - Turbo C)? #include<stdio.h>
double i;

int main()
{
    (int)(float)(char) i;
    printf("%d", sizeof((int)(float)(char)i));
    return 0;
}

Accepted Answer

Due to the C language is being platform dependent:
In Turbo C (DOS - 16 bit platform), the output will be 2.
But in GCC (Unix/Linux - 32 bit platform), the output will be 4.

What will be the output of the program in DOS (Compiler - Turbo C)? #include<stdio.h> double i; int main() { (int)(float)(char) i; printf("%d", sizeof((int)(float)(char)i)); return 0; }

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