C (Turbo C) — predict the output when using the Turbo C globals _argc and _argv. Command used: cmd sample Jan Feb Mar /* sample.c */ #include #include int main(int arc, char *arv[]) { int i; for (i = 1; i

Q: C (Turbo C) — predict the output when using the Turbo C globals _argc and _argv. Command used: cmd> sample Jan Feb Mar /* sample.c */ #include #include int main(int arc, char *arv[]) { int i; for (i = 1; i < _argc; i++) printf(…

Introduction / Context:This question tests knowledge of Turbo C's non-standard globals _argc and _argv and how they mirror the standard argc/argv. It also evaluates understanding of how command-line arguments are iterated and printed.Given Data / Assumptions:Invocation: sample Jan Feb Mar.Loop prints _argv[i] for i = 1 to _argc - 1.Each token is followed by a trailing space in the printf format.Concept / Approach:_argv[0] refers to the program name ("sample"). The loop begins at i = 1, so it prints only user-supplied arguments. The three arguments are "Jan", "Feb", and "Mar". The output will be those three separated by spaces (with a trailing space, which is visually harmless).Step-by-Step Solution:1) _argc equals 4: {"sample", "Jan", "Feb", "Mar"}.2) Loop i = 1..3 prints "Jan ", "Feb ", "Mar ".3) Combined visible output: "Jan Feb Mar".Verification / Alternative check:Changing the command to sample A B prints "A B". Starting at i = 0 would also print the program name, which this code intentionally avoids.Why Other Options Are Wrong:No output: The loop iterates three times.sample Jan Feb Mar: The code starts from i = 1, not 0.Error: The code compiles in Turbo C where _argc/_argv are available.Common Pitfalls:Assuming standard C only; here the code relies on Turbo C extensions but still runs as intended in that environment.Final Answer:Jan Feb Mar

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C (Turbo C) — predict the output when using the Turbo C globals _argc and _argv. Command used: cmd> sample Jan Feb Mar /* sample.c */ #include #include int main(int arc, char *arv[]) { int i; for (i = 1; i < _argc; i++) printf(…

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Introduction / Context:This question tests knowledge of Turbo C's non-standard globals _argc and _argv and how they mirror the standard argc/argv. It also evaluates understanding of how command-line arguments are iterated and printed.Given Data / Assumptions:Invocation: sample Jan Feb Mar.Loop prints _argv[i] for i = 1 to _argc - 1.Each token is followed by a trailing space in the printf format.Concept / Approach:_argv[0] refers to the program name ("sample"). The loop begins at i = 1, so it prints only user-supplied arguments. The three arguments are "Jan", "Feb", and "Mar". The output will be those three separated by spaces (with a trailing space, which is visually harmless).Step-by-Step Solution:1) _argc equals 4: {"sample", "Jan", "Feb", "Mar"}.2) Loop i = 1..3 prints "Jan ", "Feb ", "Mar ".3) Combined visible output: "Jan Feb Mar".Verification / Alternative check:Changing the command to sample A B prints "A B". Starting at i = 0 would also print the program name, which this code intentionally avoids.Why Other Options Are Wrong:No output: The loop iterates three times.sample Jan Feb Mar: The code starts from i = 1, not 0.Error: The code compiles in Turbo C where _argc/_argv are available.Common Pitfalls:Assuming standard C only; here the code relies on Turbo C extensions but still runs as intended in that environment.Final Answer:Jan Feb Mar

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