C (Turbo C) — predict the output when using the Turbo C globals _argc and _argv. Command used: cmd sample Jan Feb Mar /* sample.c */ #include #include int main(int arc, char *arv[]) { int i; for (i = 1; i

Q: C (Turbo C) — predict the output when using the Turbo C globals _argc and _argv. Command used: cmd> sample Jan Feb Mar /* sample.c */ #include #include int main(int arc, char *arv[]) { int i; for (i = 1; i < _argc; i++) printf(…

Introduction / Context: This question tests knowledge of Turbo C's non-standard globals _argc and _argv and how they mirror the standard argc/argv. It also evaluates understanding of how command-line arguments are iterated and printed. Given Data / Assumptions: Invocation: sample Jan Feb Mar. Loop prints _argv[i] for i = 1 to _argc - 1. Each token is followed by a trailing space in the printf format. Concept / Approach: _argv[0] refers to the program name ("sample"). The loop begins at i = 1, so it prints only user-supplied arguments. The three arguments are "Jan", "Feb", and "Mar". The output will be those three separated by spaces (with a trailing space, which is visually harmless). Step-by-Step Solution: 1) _argc equals 4: {"sample", "Jan", "Feb", "Mar"}.2) Loop i = 1..3 prints "Jan ", "Feb ", "Mar ".3) Combined visible output: "Jan Feb Mar". Verification / Alternative check: Changing the command to sample A B prints "A B". Starting at i = 0 would also print the program name, which this code intentionally avoids. Why Other Options Are Wrong: No output: The loop iterates three times. sample Jan Feb Mar: The code starts from i = 1, not 0. Error: The code compiles in Turbo C where _argc/_argv are available. Common Pitfalls: Assuming standard C only; here the code relies on Turbo C extensions but still runs as intended in that environment. Final Answer: Jan Feb Mar

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C (Turbo C) — predict the output when using the Turbo C globals _argc and _argv. Command used: cmd> sample Jan Feb Mar /* sample.c */ #include #include int main(int arc, char *arv[]) { int i; for (i = 1; i < _argc; i++) printf(…

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Introduction / Context: This question tests knowledge of Turbo C's non-standard globals _argc and _argv and how they mirror the standard argc/argv. It also evaluates understanding of how command-line arguments are iterated and printed. Given Data / Assumptions: Invocation: sample Jan Feb Mar. Loop prints _argv[i] for i = 1 to _argc - 1. Each token is followed by a trailing space in the printf format. Concept / Approach: _argv[0] refers to the program name ("sample"). The loop begins at i = 1, so it prints only user-supplied arguments. The three arguments are "Jan", "Feb", and "Mar". The output will be those three separated by spaces (with a trailing space, which is visually harmless). Step-by-Step Solution: 1) _argc equals 4: {"sample", "Jan", "Feb", "Mar"}.2) Loop i = 1..3 prints "Jan ", "Feb ", "Mar ".3) Combined visible output: "Jan Feb Mar". Verification / Alternative check: Changing the command to sample A B prints "A B". Starting at i = 0 would also print the program name, which this code intentionally avoids. Why Other Options Are Wrong: No output: The loop iterates three times. sample Jan Feb Mar: The code starts from i = 1, not 0. Error: The code compiles in Turbo C where _argc/_argv are available. Common Pitfalls: Assuming standard C only; here the code relies on Turbo C extensions but still runs as intended in that environment. Final Answer: Jan Feb Mar

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