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If an unsigned int is 2 bytes wide then, What will be the output of the program? #include int main() { unsigned int m = 32; printf("%x\n", ~m); return 0; }

ffff
0000
ffdf
ddfd

Correct Answer: ffdf

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Bitwise & and | are unary operators
Left shifting a number by 1 is always equivalent to multiplying it by 2.
Bitwise & can be used to divide a number by powers of 2
Bitwise & can be used to check if more than one bit in a number is on.
In the statement expression1 >> expression2. if expression1 is a signed integer with its leftmost bit set to 1 then on right shifting it the result of the statement will vary from computer to computer

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