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What will be the output of the program? #define P printf("%d\n", -1^~0); #define M(P) int main()\ {\ P\ return 0;\ } M(P)

1
0
-1
2

Correct Answer: 0

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Bitwise & and | are unary operators
Left shifting a number by 1 is always equivalent to multiplying it by 2.
Bitwise & can be used to divide a number by powers of 2
Bitwise & can be used to check if more than one bit in a number is on.
In the statement expression1 >> expression2. if expression1 is a signed integer with its leftmost bit set to 1 then on right shifting it the result of the statement will vary from computer to computer
Bitwise & can be used to check if a bit in number is set or not.
Left shifting an unsigned int or char by 1 is always equivalent to multiplying it by 2.

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