With math.h functions, what is the output of this code? #include<stdio.h> #include<math.h> int main() { float n = 1.54; printf("%f, %f ", ceil(n), floor(n)); return 0; } Assume default %f precision.

Introduction / Context:ceil returns the least integer value greater than or equal to the argument; floor returns the greatest integer value less than or equal to the argument. Both return double.

Given Data / Assumptions:

• n = 1.54.
• ceil(1.54) = 2.0, floor(1.54) = 1.0.
• printf uses "%f" for both values, printing six fractional digits.

Concept / Approach:Apply the definitions directly and print with fixed default precision.

Step-by-Step Solution:Compute ceil(1.54) → 2.0.Compute floor(1.54) → 1.0.printf("%f, %f") prints "2.000000, 1.000000".

Verification / Alternative check:Using integer casts would truncate toward zero, which also yields 1 for positive 1.54, but cast is not the same as floor for negative values.

Why Other Options Are Wrong:Other numeric pairs do not match the mathematical definition of ceil and floor for 1.54.

Common Pitfalls:Confusing truncation with floor for negative inputs; forgetting both functions return double.

Final Answer:2.000000, 1.000000