What is printed after casting a float to int in C?\n\n#include<stdio.h>\nint main()\n{\n float fval = 7.29;\n printf("%d\n", (int)fval);\n return 0;\n}\n\nAssume standard C semantics for casts and printf.

Introduction / Context:
Casting from float to int truncates toward zero. Printing with %d expects an int value. This question checks understanding of truncation versus rounding.

Given Data / Assumptions:

• fval = 7.29 (positive float).
• (int)fval discards the fractional part.
• printf("%d") prints the resulting integer in decimal.

Concept / Approach:
Use the truncation rule: for positive numbers, truncation is equivalent to floor; for negative numbers, truncation differs from floor.

Step-by-Step Solution:
Compute (int)7.29 → 7.printf prints 7.

Verification / Alternative check:
Testing with a negative value, e.g., (int)(-7.29) would yield -7 (truncation), whereas floor(-7.29) would be -8.

Why Other Options Are Wrong:
0, 0.0, 7.0: not consistent with truncation and %d formatting.

Common Pitfalls:
Confusing rounding with truncation; using the wrong printf format specifier.

Final Answer:
7