Function declaration syntax: choose the correct prototype for a function that takes float*** and returns float****.

Difficulty: Easy

Correct Answer: float fun(float);

Explanation:


Introduction / Context:
This is about precise C function declaration syntax with multiple pointer indirections. Reading pointer “stars” from the identifier outward helps decode parameter and return types.



Given Data / Assumptions:

  • We need a function that receives a pointer to pointer to pointer to float (float**).
  • The function must return a pointer to pointer to pointer to pointer to float (float****).
  • Standard C declaration syntax is used.


Concept / Approach:
In C, the return type precedes the function name, and parameter types go inside parentheses after the name. A quadruple pointer to float is written as float *. A triple pointer parameter is written as float in the parameter list.



Step-by-Step Solution:
Desired return type: float ****.Desired parameter type: float .Combine in a prototype: float fun(float);This precisely matches the requirement.



Verification / Alternative check:
Check with a typedef to simplify reading: typedef float F; then return is F and parameter is F; translating back confirms the same star count.



Why Other Options Are Wrong:
Options with fewer stars on return or parameter do not match the stated types (e.g., float ** or float *). A plain float return is not a pointer return. Reversing the parameter/return star counts changes the semantics.



Common Pitfalls:
Losing track of pointer levels; forgetting that the identifier binds most tightly to the nearest stars in more complex declarations.



Final Answer:
float *fun(float);

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