Pointer basics: what do the variables represent here, and which statement is correct? #include int main() { int i = 10; int *j = &i; return 0; }

Introduction / Context:This straightforward question confirms understanding of a pointer declaration and initialization in C. It asks you to identify which variable is a pointer and what address it holds.

Given Data / Assumptions:

• int i = 10; defines an integer object i.
• int *j = &i; defines j as a pointer to int, initialized to the address of i.
• No other indirection levels or arrays are used.

Concept / Approach:In C, a declaration of the form int *j means j is a pointer to an int. The ampersand operator & yields the address of its operand. Thus, &i is the address of i, and assigning that to j makes j point to i.

Step-by-Step Solution:i is a plain integer with value 10.j is declared with a star, so it is a pointer to int.j is initialized with &i, meaning j stores the address where i lives.Therefore, *j would yield the value 10 if dereferenced later.

Verification / Alternative check:Adding printf statements like printf("%d", *j); would print 10, demonstrating that j indeed points to i. Printing j with %p would show a nonzero address value.

Why Other Options Are Wrong:i is not a pointer; it is an int. j is not a pointer to a pointer (that would be int *j;). Claiming both are pointers or both are identical integers is incorrect.

Common Pitfalls:Misplacing the star (e.g., int j, int *j—stylistic spacing does not change meaning); confusing the value stored in i with the address stored in j.

Final Answer:j is a pointer to an int and stores address of i