Difficulty: Easy
Correct Answer: fbc = (M * y1) / I
Explanation:
Introduction / Context:Bending stress distribution in beams is a fundamental topic in strength of materials and steel design. Whether the beam is a rolled section or a built-up section, the flexure formula connects internal bending moment, section properties, and fiber distance from the neutral axis to compute compressive or tensile stresses.
Given Data / Assumptions:
Concept / Approach:The elementary flexure (bending) formula states: sigma = M * y / I. Stress varies linearly with y; it is compressive above the neutral axis (in sagging) and tensile below. For the extreme compression fiber, y = y1, so the actual bending compressive stress is computed directly by substituting y1 into the formula.
Step-by-Step Solution:
Start with the flexure relation: sigma = M * y / I.Select the compression edge: y = y1 (distance from N.A. to the extreme compression fiber).Compute: fbc = (M * y1) / I.If desired, use section modulus Z = I / y1 to write: fbc = M / Z (equivalent when y = y1).Verification / Alternative check:Cross-check by computing Z about the compression edge (Z = I / y1). Then fbc = M / Z. Both forms are algebraically identical and yield the same stress.
Why Other Options Are Wrong:Forms such as I / (M * y1), M / (I * y1), or (I * y1) / M invert or scramble the flexure relation. They do not match the linear-elastic bending theory. M / Z is correct only if Z corresponds to the same edge, which is implicit but often not stated in quick formulas.
Common Pitfalls:Using the wrong axis for I; mixing up y for tension vs. compression side; applying plastic section modulus instead of elastic section modulus when the question clearly assumes elastic behavior.
Final Answer:fbc = (M * y1) / I
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