Difficulty: Easy
Correct Answer: 94 m^3
Explanation:
Introduction / Context:
In earthwork, material quantity is governed by conservation of dry mass. When compacting soil from a borrow pit into an embankment at a different dry density, the required borrow volume changes accordingly. This is a frequent calculation in planning haul quantities and estimating cost and time for construction.
Given Data / Assumptions:
Concept / Approach:
Conserve dry mass M_d. Dry mass placed in embankment equals dry mass removed from borrow: M_d = ρ_d,borrow * V_borrow = ρ_d,emb * V_emb. Solve for V_borrow. This avoids the need for water-content data when only dry densities are involved.
Step-by-Step Solution:
Verification / Alternative check:
Because the embankment has a lower dry density than the borrow, a slightly smaller borrow volume than 100 m^3 is needed; the 94 m^3 result matches that expectation.
Why Other Options Are Wrong:
106 m^3 assumes the opposite density relation; 100 m^3 ignores density differences; 90 m^3 underestimates mass requirements.
Common Pitfalls:
Using bulk (wet) densities or moisture contents unnecessarily, or confusing which density is higher. The conservation should always be done on dry mass when densities are given as dry.
Final Answer:
94 m^3
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