Difficulty: Medium
Correct Answer: 625000
Explanation:
Introduction:
The impeller Reynolds number is a key dimensionless group in mixing that indicates the flow regime (laminar, transitional, or fully turbulent). Correctly calculating Re from density, viscosity, impeller size, and rotational speed helps decide correlations for power number, mass transfer, and scale-up in bioprocess engineering.
Given Data / Assumptions:
Concept / Approach:
For agitated vessels, the Reynolds number incorporates rotational speed and impeller diameter squared. Unit consistency is essential: convert g/mL to kg/m^3, cm to m, and rpm to s^-1 before substitution.
Step-by-Step Solution:
Step 1: Convert units: rho = 2500 kg/m^3; D = 0.50 m; N = 120 rpm = 120/60 = 2.0 s^-1; mu = 0.002 kg/(m·s).Step 2: Apply Re = (rho * N * D^2) / mu.Step 3: Compute D^2 = 0.50^2 = 0.25 m^2.Step 4: Numerator = 2500 * 2.0 * 0.25 = 1250.Step 5: Re = 1250 / 0.002 = 625000.
Verification / Alternative check:
Magnitude check: with high density and moderate viscosity, Re in the 10^5–10^6 range is expected for a 0.5 m impeller at 120 rpm, confirming turbulent flow.
Why Other Options Are Wrong:
Common Pitfalls:
Mixing units (rpm vs s^-1), forgetting to square D, or using kinematic viscosity instead of dynamic viscosity without proper conversion (nu = mu/rho).
Final Answer:
625000
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