In the following coded letter analogy, BDFH is related to YWUS by a specific alphabet complement pattern. Applying the same pattern, JLNP is related to which of the following options?

Introduction / Context:
This problem is a coded letter analogy that uses complementary letter positions in the alphabet. You are told that BDFH maps to YWUS and must find the corresponding mapping for JLNP. Solving this requires identifying how each letter is transformed and then applying the same letter wise rule to the new sequence.

Given Data / Assumptions:
- First letter group: BDFH.
- Related group: YWUS.
- Second base group: JLNP.
- Answer options: QOMK, ACEF, ZXUT and UVWX.
- We assume that each letter position transforms individually via a consistent pattern rather than arbitrary whole word replacement.

Concept / Approach:
Assign positions to letters: A is 1, B is 2, ..., Z is 26. For BDFH, the positions are 2, 4, 6 and 8. For YWUS, the positions are 25, 23, 21 and 19. Notice that each pair of positions sums to 27: 2 + 25 = 27, 4 + 23 = 27, 6 + 21 = 27 and 8 + 19 = 27. Thus each letter is replaced by its complement whose position adds up to 27, a common mirror rule about the centre of the alphabet. We apply the same rule to JLNP.

Step-by-Step Solution:
Step 1: Confirm that BDFH to YWUS follows the 27 sum complement rule. Step 2: Convert JLNP to positions. J is 10, L is 12, N is 14 and P is 16. Step 3: For each position x, compute 27 minus x. For J, 27 - 10 = 17 which is Q. For L, 27 - 12 = 15 which is O. For N, 27 - 14 = 13 which is M. For P, 27 - 16 = 11 which is K. Step 4: Write the mapped sequence as QOMK. Step 5: Compare QOMK with the answer options and choose it.

Verification / Alternative check:
Verify sums: 10 (J) plus 17 (Q) is 27, 12 (L) plus 15 (O) is 27, 14 (N) plus 13 (M) is 27, and 16 (P) plus 11 (K) is 27. The pattern is identical to the one used for BDFH. None of the other options produce such consistent complementary pairs across all positions, so QOMK is uniquely correct.

Why Other Options Are Wrong:
Option B ACEF does not correspond to complementary positions for each letter in JLNP. Option C ZXUT and option D UVWX similarly fail the 27 sum test for all pairs and appear to be distractors based on other patterns. Since a single strict rule must govern the analogy, any option that does not follow the complement rule throughout cannot be accepted.

Common Pitfalls:
A common mistake is to assume a simple shift by a fixed number of positions without checking whether this works for the entire group. Another is to correctly identify the complement for one or two letters but fail to test it on all letters before choosing an answer. Writing positions and verifying sums is the safest method to avoid these errors.

Final Answer:
Using the same alphabet complement rule that maps BDFH to YWUS, JLNP maps to QOMK.